MHT CET · Chemistry · Solutions
A solution of non volatile solute is obtained by dissolving 2 g in 50 g benzene. Calculate the vapour pressure of solution if vapour pressure of pure benzene is 640 mmHg at \(25^{\circ} \mathrm{C}\).
[mol. mass of benzene \(=78 \mathrm{~g} \mathrm{~mol}^{-1}\), mol. mass of solute \(\left.=64 \mathrm{~g} \mathrm{~mol}^{-1}\right]\)
- A 600.21 mm Hg
- B 604.52 mm Hg
- C 608.64 mm Hg
- D 612.83 mm Hg
Answer & Solution
Correct Answer
(C) 608.64 mm Hg
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \quad \frac{\Delta \mathrm{P}}{\mathrm{P}^0}= & \frac{\mathrm{P}^0-\mathrm{P}}{\mathrm{P}^0}=\mathrm{x}_2=\frac{\mathrm{W}_2 \mathrm{M}_1}{\mathrm{~W}_1 \mathrm{M}_2} \\ \therefore \quad \frac{640-\mathrm{P}}{640} & =\frac{2 \times 78}{50 \times 64} \\ 640-\mathrm{P} & =640 \times 0.048 \\ \mathrm{P} & =640-31.2 \\ \mathrm{P} & =608.8 \mathrm{~mm} \mathrm{Hg}\end{aligned}\)
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