MHT CET · Chemistry · Solutions
A solution of non volatile solute has boiling point elevation 1.75 K .
Calculate molality of solution \(\left[\mathrm{K}_{\mathrm{b}}=3.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]\)
- A \(0.77 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- B \(0.69 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- C \(0.50 \mathrm{~mol} \mathrm{~kg}^{-1}\)
- D \(0.35 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.50 \mathrm{~mol} \mathrm{~kg}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \mathrm{m} \\ & 1.75 \mathrm{~K}=3.5 \mathrm{Kkg} \mathrm{mol}^{-1} \times \mathrm{m} \\ & \mathrm{m}=\frac{1.75}{3.5}=0.50 \mathrm{~mol} \mathrm{~kg}^{-1}\end{aligned}\)
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