ExamBro
ExamBro
MHT CET · Chemistry · Solutions

A solution of non volatile solute has boiling point elevation 0.5 K . Calculate molality of solution \(\left[\mathrm{K}_{\mathrm{b}}=2.40 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\right]\).

  1. A \(0.12 \mathrm{~mol} \mathrm{~kg}^{-1}\)
  2. B \(0.21 \mathrm{~mol} \mathrm{~kg}^{-1}\)
  3. C \(0.16 \mathrm{~mol} \mathrm{~kg}^{-1}\)
  4. D \(0.28 \mathrm{~mol} \mathrm{~kg}^{-1}\).
Verified Solution

Answer & Solution

Correct Answer

(B) \(0.21 \mathrm{~mol} \mathrm{~kg}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \Delta \mathrm{T}_{\mathrm{b}}=\mathrm{K}_{\mathrm{b}} \times \mathrm{m} \\ & 0.5 \mathrm{~K}=2.40 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1} \times \mathrm{m} \\ \therefore \quad & \mathrm{m}=\frac{0.5}{2.40}=0.21 \mathrm{~mol} \mathrm{~kg}^{-1}\end{aligned}\)