MHT CET · Chemistry · Ionic Equilibrium
A monobasic weak acid dissociates to \(1.2 \%\) in its 0.01 M solution at 298 K . Calculate dissociation constant of it.
- A \(1.04 \times 10^{-8}\)
- B \(1.44 \times 10^{-6}\)
- C \(1.30 \times 10^{-6}\)
- D \(1.18 \times 10^{-5}\)
Answer & Solution
Correct Answer
(B) \(1.44 \times 10^{-6}\)
Step-by-step Solution
Detailed explanation
\(\alpha = \frac{1.2}{100} = 0.012\) \(K_a = C\alpha^2\)
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