MHT CET · Chemistry · Ionic Equilibrium
A monobasic weak acid dissociates \(2 \%\) in its 0.002 M solution.
Calculate the dissociation constant of weak acid.
- A \(2 \times 10^{-9}\)
- B \(8 \times 10^{-7}\)
- C \(6 \times 10^{-7}\)
- D \(4 \times 10^{-6}\)
Answer & Solution
Correct Answer
(B) \(8 \times 10^{-7}\)
Step-by-step Solution
Detailed explanation
\(\alpha = \frac{2}{100} = 0.02\) \(K_a = C\alpha^2\)
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