MHT CET · Chemistry · Solid State
A metal crystallises in bcc structure with edge length \(4 \times 10^{-8}\). If density of unit cell is \(10 \mathrm{~g} \mathrm{~cm}^{-3}\). What is its molar mass?
- A \(60 \mathrm{~g} \mathrm{~mol}^{-1}\)
- B \(152 \mathrm{~g} \mathrm{~mol}^{-1}\)
- C \(120 \mathrm{~g} \mathrm{~mol}^{-1}\)
- D \(193 \mathrm{~g} \mathrm{~mol}^{-1}\)
Answer & Solution
Correct Answer
(D) \(193 \mathrm{~g} \mathrm{~mol}^{-1}\)
Step-by-step Solution
Detailed explanation
For bec unit cell, \(\mathrm{n}=2\).
\(\text {Density }(\rho)=\frac{M \times n}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}} \)
\( 10 \mathrm{~g} \mathrm{~cm}^{-3}=\frac{\mathrm{M} \times 2}{\left(4 \times 10^{-8} \mathrm{~cm}\right)^3 \times 6.022 \times 10^{23} \mathrm{~mol}^{-1}} \)
\( \mathrm{M}=\frac{6.022 \times 10^{23} \mathrm{~mol}^{-1} \times\left(4 \times 10^{-8} \mathrm{~cm}^3 \times 10 \mathrm{~g} \mathrm{~cm}^{-3}\right.}{2} \)
\( \therefore \quad M=193 \mathrm{~g} \mathrm{~mol}^{-1}\)
\(\text {Density }(\rho)=\frac{M \times n}{\mathrm{a}^3 \mathrm{~N}_{\mathrm{A}}} \)
\( 10 \mathrm{~g} \mathrm{~cm}^{-3}=\frac{\mathrm{M} \times 2}{\left(4 \times 10^{-8} \mathrm{~cm}\right)^3 \times 6.022 \times 10^{23} \mathrm{~mol}^{-1}} \)
\( \mathrm{M}=\frac{6.022 \times 10^{23} \mathrm{~mol}^{-1} \times\left(4 \times 10^{-8} \mathrm{~cm}^3 \times 10 \mathrm{~g} \mathrm{~cm}^{-3}\right.}{2} \)
\( \therefore \quad M=193 \mathrm{~g} \mathrm{~mol}^{-1}\)
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