MHT CET · Chemistry · States of Matter
A hot air balloon has volume of \(2000 \mathrm{dm}^3\) at \(99^{\circ} \mathrm{C}\). What is the new volume if air in balloon cools to \(80^{\circ} \mathrm{C}\) ?
- A \(2428.9 \mathrm{dm}^3\)
- B \(2656.9 \mathrm{dm}^3\)
- C \(2814.9 \mathrm{dm}^3\)
- D \(1897.8 \mathrm{dm}^3\)
Answer & Solution
Correct Answer
(D) \(1897.8 \mathrm{dm}^3\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{ll} & \text { Using Charles' law, } \\ & \frac{\mathrm{V}_1}{\mathrm{~T}_1}=\frac{\mathrm{V}_2}{\mathrm{~T}_2} \\ \therefore \quad & \frac{2000 \mathrm{dm}^3}{372 \mathrm{~K}}=\frac{\mathrm{V}_2}{353 \mathrm{~K}} \\ \therefore \quad & \mathrm{V}_2=\frac{2000 \times 353}{372}=1897.8 \mathrm{dm}^3\end{array}\)
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