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MHT CET · Chemistry · Thermodynamics (C)

A gas performs 0.320 kJ work on surrounding and absorbs 120 J of heat from the surrounding. Hence, change in internal energy is

  1. A 200 J
  2. B 120.32 J
  3. C -200 J
  4. D 440 J
Verified Solution

Answer & Solution

Correct Answer

(C) -200 J

Step-by-step Solution

Detailed explanation

According to first law of thermodynamics,
ΔU=q+W
Since, work is does on the surrounding.
So, W=-0.320KJ
=-320J
q=120J
ΔU=-320+120
=-200J