MHT CET · Chemistry · Thermodynamics (C)
A gas is allowed to expand against a constant external pressure of 2.5 bar from an initial volume ' \(x\) ' \(L\) to final volume of \(4.5 \mathrm{~L}\). If amount of work done is \(5 \mathrm{dm}^3\) bar, what is the value of ' \(x\) '?
- A 2.5 L
- B 4.5 L
- C 6.0 L
- D 1.2 L
Answer & Solution
Correct Answer
(A) 2.5 L
Step-by-step Solution
Detailed explanation
1.2 Work done \(=-5\) bar. \(\mathrm{dm}^3\) (due to expansion work done will be negative)
\(
\mathrm{W}=-\operatorname{Pext}\left[\mathrm{V}_2-\mathrm{V}_1\right] \quad\left(1 \mathrm{~L}=1 \mathrm{dm}^3\right)
\)
\(
-5 \text { bar- } \mathrm{dm}^3=-2.5 \text { bar }[4.5-\mathrm{x}] \mathrm{dm}^3
\)
\(4.5-\mathrm{x}=\frac{5}{2.5}\)
\(
\begin{aligned}
& 4.5-x=2 \\
& x=4.5-2 \\
& x=2.5 L
\end{aligned}
\)
\(
\mathrm{W}=-\operatorname{Pext}\left[\mathrm{V}_2-\mathrm{V}_1\right] \quad\left(1 \mathrm{~L}=1 \mathrm{dm}^3\right)
\)
\(
-5 \text { bar- } \mathrm{dm}^3=-2.5 \text { bar }[4.5-\mathrm{x}] \mathrm{dm}^3
\)
\(4.5-\mathrm{x}=\frac{5}{2.5}\)
\(
\begin{aligned}
& 4.5-x=2 \\
& x=4.5-2 \\
& x=2.5 L
\end{aligned}
\)
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