MHT CET · Chemistry · Thermodynamics (C)
A gas expands isothermally against a constant external pressure of 1 bar from \(10 \mathrm{dm}^3\) to \(20 \mathrm{dm}^3\) by absorbing 800 J of heat from surrounding. Calculate value of \(\Delta \mathrm{U}\).
- A 100 J
- B \(-200 \mathrm{~J}\)
- C 200 J
- D -300 J
Answer & Solution
Correct Answer
(B) \(-200 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{P}_{\mathrm{ext}}=1 \mathrm{bar} \)
\( \mathrm{V}_1=10 \mathrm{dm}^3, \mathrm{~V}_2=20 \mathrm{dm}^3 \)
\( \mathrm{Q}=800 \mathrm{~J} \)
\( \mathrm{W}=-\mathrm{P}_{\mathrm{ext}}\left(\mathrm{V}_2-\mathrm{V}_1\right)=-1 \mathrm{bar}\) \(\left(20 \mathrm{dm}^3-10 \mathrm{dm}^3\right) \)
\(=-10 \mathrm{dm}^3 \mathrm{bar}=-1000 \mathrm{~J} \)
\( \Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}=800 \mathrm{~J}-1000 \mathrm{~J}=-200 \mathrm{~J}\)
\( \mathrm{V}_1=10 \mathrm{dm}^3, \mathrm{~V}_2=20 \mathrm{dm}^3 \)
\( \mathrm{Q}=800 \mathrm{~J} \)
\( \mathrm{W}=-\mathrm{P}_{\mathrm{ext}}\left(\mathrm{V}_2-\mathrm{V}_1\right)=-1 \mathrm{bar}\) \(\left(20 \mathrm{dm}^3-10 \mathrm{dm}^3\right) \)
\(=-10 \mathrm{dm}^3 \mathrm{bar}=-1000 \mathrm{~J} \)
\( \Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}=800 \mathrm{~J}-1000 \mathrm{~J}=-200 \mathrm{~J}\)
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