MHT CET · Chemistry · Thermodynamics (C)
A gas absorbs \(150 \mathrm{~J}\) heat and expands by \(300 \mathrm{~cm}^3\) against a constant external pressure \(2 \times 10^5 \mathrm{~N} \mathrm{~m}^{-2}\), What is \(\Delta \mathrm{U}\) of the system?
- A \(210 \mathrm{~J}\)
- B \(90 \mathrm{~J}\)
- C \(450 \mathrm{~J}\)
- D \(-300 \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(90 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(300 \mathrm{~cm}^3=300 \times 10^{-6} \mathrm{~m}^3 \mathrm{~W} \)
\( =-\mathrm{P}_{\text {ext }} \Delta \mathrm{V} \)
\( =-2 \times 10^5 \mathrm{~N} \mathrm{~m}^{-2} \times\left(300 \times 10^{-6} \mathrm{~m}^3\right) \)
\( =-60 \mathrm{~N} \mathrm{~m} \)
\( =-60 \mathrm{~J} \)
\( \therefore \mathrm{W} =-60 \mathrm{~J}\)
Now,
\(\therefore \Delta \mathrm{U} =\mathrm{q}+\mathrm{P}_{\text {ext }} \Delta \mathrm{V} \)
\( =150 \mathrm{~J}+(-60 \mathrm{~J}) \)
\( =90 \mathrm{~J}\)
\( =-\mathrm{P}_{\text {ext }} \Delta \mathrm{V} \)
\( =-2 \times 10^5 \mathrm{~N} \mathrm{~m}^{-2} \times\left(300 \times 10^{-6} \mathrm{~m}^3\right) \)
\( =-60 \mathrm{~N} \mathrm{~m} \)
\( =-60 \mathrm{~J} \)
\( \therefore \mathrm{W} =-60 \mathrm{~J}\)
Now,
\(\therefore \Delta \mathrm{U} =\mathrm{q}+\mathrm{P}_{\text {ext }} \Delta \mathrm{V} \)
\( =150 \mathrm{~J}+(-60 \mathrm{~J}) \)
\( =90 \mathrm{~J}\)
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