MHT CET · Chemistry · Chemical Kinetics
A first order reaction has a rate constant \(0.00813 \mathrm{~min}^{-1}\). How long will it take for \(60 \%\)
completion?
- A \(98.7 \mathrm{~min}\)
- B \(56.35 \mathrm{~min}\)
- C \(112.7 \mathrm{~min}\)
- D \(62 \cdot 77 \mathrm{~min}\)
Answer & Solution
Correct Answer
(C) \(112.7 \mathrm{~min}\)
Step-by-step Solution
Detailed explanation
(A)
Original amount of reactant \(=100\)
\([\mathrm{A}]_{t}=\) Reactant remaining unreacted \(=100-60=40\)
For first order reaction,
\(\therefore t=\frac{2.303}{0.00813 \mathrm{~min}^{-1}} \log _{10} \frac{100}{40}=112.7 \mathrm{~min}\)
Original amount of reactant \(=100\)
\([\mathrm{A}]_{t}=\) Reactant remaining unreacted \(=100-60=40\)
For first order reaction,
\(\therefore t=\frac{2.303}{0.00813 \mathrm{~min}^{-1}} \log _{10} \frac{100}{40}=112.7 \mathrm{~min}\)
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