MHT CET · Chemistry · Electrochemistry
A conductivity cell shows resistance of \(600 \mathrm{ohm}\). If conductivity of \(0.01 \mathrm{M} \mathrm{KCl}\) is \(0.0015 \Omega^{-1} \mathrm{~cm}^{-1}\), what is cell constant?
- A \(0.60 \mathrm{~cm}^{-1}\)
- B \(0.45 \mathrm{~cm}^{-1}\)
- C \(0.90 \mathrm{~cm}^{-1}\)
- D \(75 \mathrm{~cm}^{-1}\)
Answer & Solution
Correct Answer
(C) \(0.90 \mathrm{~cm}^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{R}=600 \Omega, \mathrm{k}_{\mathrm{KCl}}=0.0015 \Omega^{-} \mathrm{cm}^{-1}, \mathrm{c}=\) \(0.01 \mathrm{M} \text { Cell constant }=\)
\(\mathrm{k}_{\mathrm{KCl}} \times \mathrm{R}_{\text {solution }}=0.0015 \Omega^{-1} \mathrm{~cm}^{-1}~ \times\) \(600 \Omega=0.90 \mathrm{~cm}^{-1}\)
\(\mathrm{k}_{\mathrm{KCl}} \times \mathrm{R}_{\text {solution }}=0.0015 \Omega^{-1} \mathrm{~cm}^{-1}~ \times\) \(600 \Omega=0.90 \mathrm{~cm}^{-1}\)
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