ExamBro
ExamBro
MHT CET · Chemistry · Electrochemistry

A conductivity cell containing \(0.001 \mathrm{M} \mathrm{AgNO}_3\) solution develops resistance \(6530 \mathrm{ohm}\) at \(25^{\circ} \mathrm{C}\). Calculate the electrical conductivity of solution at same temperature if the cell constant is \(0.653 \mathrm{~cm}^{-1}\).

  1. A \(1.3 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\)
  2. B \(1.5 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\)
  3. C \(1.7 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\)
  4. D \(1.0 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(1.0 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\)

Step-by-step Solution

Detailed explanation

\(\begin{array}{ll} & \text { Cell constant }=\mathrm{k} \times \mathrm{R} \\ \therefore & 0.653=\mathrm{k} \times 6530 \\ \therefore & \mathrm{k}=\frac{0.653}{6530}=1 \times 10^{-4} \Omega^{-1} \mathrm{~cm}^{-1}\end{array}\)