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MHT CET · Chemistry · Chemical Kinetics

A complex reaction takes place in following steps.
\(\begin{aligned}
& \mathrm{NO}_2 \mathrm{Cl}_{(\mathrm{g})} \longrightarrow \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{Cl}_{(\mathrm{g})} \text { (slow) } \\
& \mathrm{NO}_2 \mathrm{Cl}_{(\mathrm{g})}+\mathrm{Cl}_{(\mathrm{g})} \longrightarrow \mathrm{NO}_{2(\mathrm{~g})}+\mathrm{Cl}_{2(\mathrm{~g})} \text { (fast) }
\end{aligned}\)
Identify rate law equation for this reaction.

  1. A \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2 \mathrm{Cl}\right]\)
  2. B \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2\right][\mathrm{Cl}]\)
  3. C \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2\right]^2\)
  4. D \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2 \mathrm{Cl}\right]^2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2 \mathrm{Cl}\right]\)

Step-by-step Solution

Detailed explanation

Rate law is determined by the slow step: \(\mathrm{r}=\mathrm{k}\left[\mathrm{NO}_2 \mathrm{Cl}\right]\)
From MHT CET
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