MHT CET · Chemistry · States of Matter
A closed container contains mixture of non-reacting gases A and B. Partial pressure of \(A\) and \(B\) are 4.5 bar and 5.5 . bar respectively. Find mole fraction of \(\mathrm{A}\) and \(\mathrm{B}\) respectively.
- A 0.035 and 0.065
- B 0.055 and 0.045
- C 0.45 and 0.55
- D 0.55 and 0.45
Answer & Solution
Correct Answer
(C) 0.45 and 0.55
Step-by-step Solution
Detailed explanation
\(\begin{aligned} \mathrm{P}_{\text {Total }}=\mathrm{P}_{\mathrm{A}}+\mathrm{P}_{\mathrm{B}} & =4.5+5.5 \\ & =10.0 \mathrm{bar}\end{aligned}\)
\(\mathrm{P}_{\mathrm{A}}=x_{\mathrm{A}} \times \mathrm{P}_{\text {Total }}\)
\(x_{\mathrm{A}}=\frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\text {Total }}}=\frac{4.5}{10}=0.45\)
\(x_{\mathrm{B}}=\frac{\mathrm{P}_{\mathrm{B}}}{\mathrm{P}_{\text {Total }}}=\frac{5.5}{10}=0.55\)
\(\mathrm{P}_{\mathrm{A}}=x_{\mathrm{A}} \times \mathrm{P}_{\text {Total }}\)
\(x_{\mathrm{A}}=\frac{\mathrm{P}_{\mathrm{A}}}{\mathrm{P}_{\text {Total }}}=\frac{4.5}{10}=0.45\)
\(x_{\mathrm{B}}=\frac{\mathrm{P}_{\mathrm{B}}}{\mathrm{P}_{\text {Total }}}=\frac{5.5}{10}=0.55\)
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