MHT CET · Chemistry · Ionic Equilibrium
A buffer solution contains equal concentrations of weak acid and its salt with strong base. Calculate pH of buffer solution if dissociation constant of weak acid is \(1.8 \times 10^{-5}\).
- A 4.7447
- B 5.142
- C 5.8496
- D 4.0128
Answer & Solution
Correct Answer
(A) 4.7447
Step-by-step Solution
Detailed explanation
For an acidic buffer,
\(\therefore \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{[\text { Salt }]}{[\text { Acid }]} \)
\( (\because[\text { Salt }]=[\text { Acid }]) \)
\(\therefore \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}=-\log \mathrm{K}_{\mathrm{a}}=-\log \left(1.8 \times 10^{-5}\right) \)
\(\therefore \mathrm{pH}=-[\log 1.8-5 \log 10]=4.7447\)
\(\therefore \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}+\log \frac{[\text { Salt }]}{[\text { Acid }]} \)
\( (\because[\text { Salt }]=[\text { Acid }]) \)
\(\therefore \mathrm{pH}=\mathrm{pK}_{\mathrm{a}}=-\log \mathrm{K}_{\mathrm{a}}=-\log \left(1.8 \times 10^{-5}\right) \)
\(\therefore \mathrm{pH}=-[\log 1.8-5 \log 10]=4.7447\)
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