MHT CET · Chemistry · Solutions
\(450 \mathrm{mg}\) of glucose is dissolved in \(100 \mathrm{~g}\) of solvent. What is the molality of solution?
- A \(0.0025 \mathrm{~m}\)
- B \(0.025 \mathrm{~m}\)
- C \(0.25 \mathrm{~m}\)
- D \(2.5 \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(0.025 \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
Molality \(=\frac{\text { moles of solute } \times 1000}{\text { weight of solvent (in g) }}\)
Or \(=\frac{\text { weight of solute } \times 1000}{\text { mol. wt of solute } \times \text { weight of solvent (in g) }}\)
\(
=\frac{450 \times 10^{-3} \times 1000}{180 \times 100}
\)
\([\because\) Mol. mass of glucose \(=180]\)
\(=0.025 \mathrm{~m}\)
Or \(=\frac{\text { weight of solute } \times 1000}{\text { mol. wt of solute } \times \text { weight of solvent (in g) }}\)
\(
=\frac{450 \times 10^{-3} \times 1000}{180 \times 100}
\)
\([\because\) Mol. mass of glucose \(=180]\)
\(=0.025 \mathrm{~m}\)
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