MHT CET · Chemistry · Ionic Equilibrium
4 gram of NaOH is added in water to form 500 mL solution at 298 K .
What is pH of solution? (Molar mass of \(\mathrm{NaOH}=40 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(8.6990\)
- B \(10.3010\)
- C \(10.6990\)
- D \(13.3010\)
Answer & Solution
Correct Answer
(D) \(13.3010\)
Step-by-step Solution
Detailed explanation
\([\mathrm{OH^-}] = \frac{4 \mathrm{~g} / 40 \mathrm{~g} \mathrm{~mol}^{-1}}{0.5 \mathrm{~L}} = 0.2 \mathrm{~M}\) \(\mathrm{pOH} = -\log_{10}(0.2) = 0.6990\)
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