MHT CET · Chemistry · Alcohols Phenols and Ethers
\(1 \mathrm{~mol}\) alcohol reacts with Na to give what weight of hydrogen?
- A \(1 \mathrm{~g}\)
- B \(2 \mathrm{~g}\)
- C \(3 \mathrm{~g}\)
- D \(3.5 \mathrm{~g}\)
Answer & Solution
Correct Answer
(A) \(1 \mathrm{~g}\)
Step-by-step Solution
Detailed explanation
\(2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+2 \mathrm{Na} \longrightarrow 2 \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{ONa}+\mathrm{H}_{2}\)
\(\mathrm{mol}\)
mo
\(\mathrm{mol}\)
\(
\frac{1}{2} \mathrm{~mol}
\)
The weight of \(\frac{1}{2} \mathrm{~mol} \mathrm{H}_{2}=\frac{2}{2} \mathrm{~g}=1 \mathrm{~g}\)
Thus, \(1 \mathrm{~g} \mathrm{H}_{2}\) is produced when 1 mole of alcohol reacts with Na.
\(\mathrm{mol}\)
mo
\(\mathrm{mol}\)
\(
\frac{1}{2} \mathrm{~mol}
\)
The weight of \(\frac{1}{2} \mathrm{~mol} \mathrm{H}_{2}=\frac{2}{2} \mathrm{~g}=1 \mathrm{~g}\)
Thus, \(1 \mathrm{~g} \mathrm{H}_{2}\) is produced when 1 mole of alcohol reacts with Na.
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