MHT CET · Chemistry · Electrochemistry
1 C electricity deposits
- A \(10.8 \mathrm{~g}\) of \(\mathrm{Ag}\)
- B \(96500 \mathrm{~g}\) of \(\mathrm{Ag}\)
- C electrochemical equivalent of Ag
- D half of electrochemical equivalent of Ag
Answer & Solution
Correct Answer
(C) electrochemical equivalent of Ag
Step-by-step Solution
Detailed explanation
From Faraday's first law,
mass, \(w=Z \cdot Q\)
when,
\(Q=1 \mathrm{C}\)
\(w=Z=\) electrochemical equivalent.
mass, \(w=Z \cdot Q\)
when,
\(Q=1 \mathrm{C}\)
\(w=Z=\) electrochemical equivalent.
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