MHT CET · BIOLOGY · STD 12 - 5. Origin and Evolution of Life
In the population of 10,000 sheep, 4900 have homozygous dominant genotype (AA) and 4200 are heterozygous (Aa) sheep. The remaining sheep has homozygous recessive genotype (aa). Find out the frequency of Homozygous dominant allele as per Hardy-Weinberg's principle?
- A 0.7
- B 0.3
- C 0.5
- D 0.4
Answer & Solution
Correct Answer
(A) 0.7
Step-by-step Solution
Detailed explanation
According to Hardy Weinberg's law,
\(\mathrm{p}^2\) + 2pq + \(\mathrm{q}^2\) =1
(AA) 4900 (Aa) 4200 (aa) 900
Total individuals = 10000
Out of total individuals, 4900 belongs to genotype AA
AA = \(\mathrm{p}^2\) = 4900 out of 10000
\(\mathrm{p}^2\) =0.49
p = 0.7
\(\mathrm{p}^2\) + 2pq + \(\mathrm{q}^2\) =1
(AA) 4900 (Aa) 4200 (aa) 900
Total individuals = 10000
Out of total individuals, 4900 belongs to genotype AA
AA = \(\mathrm{p}^2\) = 4900 out of 10000
\(\mathrm{p}^2\) =0.49
p = 0.7
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