KCET · Physics · Semiconductors
What is the energy of the electron revolving in third orbit expressed in \( \mathrm{eV} \) ?
- A \( 1.51 \mathrm{eV} \)
- B \( 3.4 \mathrm{eV} \)
- C (4.53 eV
- D O \( 4 \mathrm{eV} \)
Answer & Solution
Correct Answer
(A) \( 1.51 \mathrm{eV} \)
Step-by-step Solution
Detailed explanation
We know that, energy of electron revolving in \( n^{\text {th }} \) orbit is given as
\( E_{n}=\frac{-13.6}{n^{2}} \)
For third orbit, \( n=3 \),
\( E_{3}=\frac{-13.6}{3^{2}}=\frac{-13.6}{9}=-1.5111 \mathrm{eV} \)
Therefore, energy of electron revolving in third orbit is \( 1.51 \mathrm{eV} \)
\( E_{n}=\frac{-13.6}{n^{2}} \)
For third orbit, \( n=3 \),
\( E_{3}=\frac{-13.6}{3^{2}}=\frac{-13.6}{9}=-1.5111 \mathrm{eV} \)
Therefore, energy of electron revolving in third orbit is \( 1.51 \mathrm{eV} \)
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