KCET · Physics · Semiconductors
The truth table given below is for ( \(A\) and \(B\) are the inputs, \(Y\) is the output).
\begin{array}{c|c|c}
\hlineA & B & Y \\
\hline 0 & 0 & 1 \\
\hline 0 & 1 & 1 \\
\hline 1 & 0 & 1 \\
\hline 1 & 1 & 0 \\
\hline
\end{array}
- A NOR
- B AND
- C XOR
- D NAND
Answer & Solution
Correct Answer
(D) NAND
Step-by-step Solution
Detailed explanation
The output \(\mathrm{Y}\) is a combination of AND + NOT gate. Hence, the truth table is for NAND gate
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