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KCET · Physics · Semiconductors

The truth table given below is for ( \(A\) and \(B\) are the inputs, \(Y\) is the output).
\begin{array}{c|c|c}
\hlineA & B & Y \\
\hline 0 & 0 & 1 \\
\hline 0 & 1 & 1 \\
\hline 1 & 0 & 1 \\
\hline 1 & 1 & 0 \\
\hline
\end{array}

  1. A NOR
  2. B AND
  3. C XOR
  4. D NAND
Verified Solution

Answer & Solution

Correct Answer

(D) NAND

Step-by-step Solution

Detailed explanation

The output \(\mathrm{Y}\) is a combination of AND + NOT gate. Hence, the truth table is for NAND gate
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