KCET · Physics · Atomic Physics
The ionisation energy of \(\mathrm{Li}^{2+}\) is equal to
- A \(9 h c R\)
- B \(6 h c R\)
- C \(2 h c R\)
- D \(h c R\)
Answer & Solution
Correct Answer
(A) \(9 h c R\)
Step-by-step Solution
Detailed explanation
Ionization energy \(=R c h Z^{2}\)
\[
Z=3 \text { for } \mathrm{Li}^{2+}
\]
\(\therefore\) Ionization energy \(=(3)^{2} R c h=9 R c h\)
\[
Z=3 \text { for } \mathrm{Li}^{2+}
\]
\(\therefore\) Ionization energy \(=(3)^{2} R c h=9 R c h\)
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