KCET · Physics · Nuclear Physics
A radioactive substance contains 10000 nuclei and its half-life period is 20 days. The number of nuclei present at the end of 10 days is
- A 7070
- B 9000
- C 8000
- D 7500
Answer & Solution
Correct Answer
(A) 7070
Step-by-step Solution
Detailed explanation
We know, \(\frac{N}{N_{0}}=\left(\frac{1}{2}\right)^{t / T}\)
\(\Rightarrow \quad \frac{N}{10000}=\left(\frac{1}{2}\right)^{10 / 20}\)
\(\Rightarrow \quad N=\frac{10000}{\sqrt{2}}=\frac{10000}{1.414}=7070\)
\(\Rightarrow \quad \frac{N}{10000}=\left(\frac{1}{2}\right)^{10 / 20}\)
\(\Rightarrow \quad N=\frac{10000}{\sqrt{2}}=\frac{10000}{1.414}=7070\)
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