KCET · Physics · Nuclear Physics
A radioactive element forms its own isotope after 3 consecutive disintegrations. The particles emitted are
- A \(3 \beta\)-particles
- B \(2 \beta\)-particles and \(1 \alpha\)-particle
- C \(2 \beta\)-particles and \(1 \gamma\)-particle
- D \(2 \alpha\)-particles and \(1 \beta\)-particle
Answer & Solution
Correct Answer
(B) \(2 \beta\)-particles and \(1 \alpha\)-particle
Step-by-step Solution
Detailed explanation
To form its own isotope atomic number (Z) should remain same.
So, the emission of one \(\alpha\)-particle and two \(\beta\)-particles will maintain the \(Z\) same.
where \(\alpha\)-particle \(={ }_{2} \mathrm{He}^{4}\); b-particle \(={ }_{-1} \beta^{0}\)
So, the emission of one \(\alpha\)-particle and two \(\beta\)-particles will maintain the \(Z\) same.
where \(\alpha\)-particle \(={ }_{2} \mathrm{He}^{4}\); b-particle \(={ }_{-1} \beta^{0}\)
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