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KCET · Physics · Ray Optics

A monochromatic beam of light is travelling from medium \(A\) of refractive index \(n_{1}\) to a medium \(\mathrm{B}\) of refractive index \(\mathrm{n}_{2}\). In the medium \(A\), there are \(x\) number of waves in certain distance. In the medium B, there are \(y\) number of waves in the same distance. Then, refractive index of medium \(A\) with respect to medium \(B\) is

  1. A \(\frac{x}{y}\)
  2. B \(\frac{y}{x}\)
  3. C \(\sqrt{\frac{x}{y}}\)
  4. D \(\frac{x}{y-x}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{x}{y}\)

Step-by-step Solution

Detailed explanation

If \(x\) number of waves of wavelength \(\lambda_{1}\) and \(y\) number of waves of wavelength \(\lambda_{2}\) are present in same distance s, then
\(\mathrm{s}=\mathrm{x} \lambda_{1}=\mathrm{y} \lambda_{2} \)
\(\text {or } \frac{\mathrm{x}}{\mathrm{y}}=\frac{\lambda_{2}}{\lambda_{1}}=\frac{\mathrm{n}_{1}}{\mathrm{n}_{2}} \)
\(\therefore \frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\frac{\mathrm{x}}{\mathrm{y}}\)