KCET · Maths · Three Dimensional Geometry
The value of \({ }^{16} C_{9}+{ }^{16} C_{10}-{ }^{16} C_{6}-{ }^{16} C_{7}\) is
- A 0
- B 1
- C \({ }^{\prime \prime} C_{0}\)
- D \({ }^{17} C_{3}\)
Answer & Solution
Correct Answer
(A) 0
Step-by-step Solution
Detailed explanation
We have,
\(\begin{aligned}
&{ }^{16} C_{9}+{ }^{16} C_{10}-{ }^{16} C_{6}-{ }^{16} C_{7} \\
&{ }^{16} C_{9}+{ }^{16} C_{10}-{ }^{16} C_{10}-{ }^{16} C_{9}\left[\because{ }^{n} C_{r}={ }^{n} C_{n-r}\right]=0
\end{aligned}\)
\(\begin{aligned}
&{ }^{16} C_{9}+{ }^{16} C_{10}-{ }^{16} C_{6}-{ }^{16} C_{7} \\
&{ }^{16} C_{9}+{ }^{16} C_{10}-{ }^{16} C_{10}-{ }^{16} C_{9}\left[\because{ }^{n} C_{r}={ }^{n} C_{n-r}\right]=0
\end{aligned}\)
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