KCET · Maths · Binomial Theorem
The last digit of number \(7^{886}\) is
- A 9
- B 7
- C 3
- D 1
Answer & Solution
Correct Answer
(A) 9
Step-by-step Solution
Detailed explanation
Since, \(\quad 7^{1}=7\)
\(7^{2}=49,7^{3}=343,7^{4}=2401\)
\(\therefore \quad 7^{886}=\left(7^{4}\right)^{221} 7^{2}\)
\(\therefore\) The last digit number \(7^{886}\) is 9 .
\(7^{2}=49,7^{3}=343,7^{4}=2401\)
\(\therefore \quad 7^{886}=\left(7^{4}\right)^{221} 7^{2}\)
\(\therefore\) The last digit number \(7^{886}\) is 9 .
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