ExamBro
ExamBro
KCET · Maths · Three Dimensional Geometry

The equation of the line through the point \((0,1,2)\) and perpendicular to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}\) is

  1. A \(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}\)
  2. B \(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)
  3. C \(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}\)
  4. D \(\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)

Step-by-step Solution

Detailed explanation

\(\mathrm{a}_1 \mathrm{a}_2+\mathrm{b}_1 \mathrm{~b}_2+\mathrm{c}_1 \mathrm{c}_2=0\)