KCET · Maths · Three Dimensional Geometry
The equation of the line through the point \((0,1,2)\) and perpendicular to the line \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}\) is
- A \(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{-3}\)
- B \(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)
- C \(\frac{x}{3}=\frac{y-1}{4}=\frac{z-2}{3}\)
- D \(\frac{x}{3}=\frac{y-1}{-4}=\frac{z-2}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{x}{-3}=\frac{y-1}{4}=\frac{z-2}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{a}_1 \mathrm{a}_2+\mathrm{b}_1 \mathrm{~b}_2+\mathrm{c}_1 \mathrm{c}_2=0\)
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