KCET · Chemistry · Solutions
Which of the following pair of solutions is isotonic?
- A \(0.01 \mathrm{M} \mathrm{BaCl}_{2}\) and \(0.015 \mathrm{M} \mathrm{NaCl}\)
- B \(0.001 \mathrm{M} \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\) and \(0.001 \mathrm{M} \mathrm{BaCl}_{2}\)
- C \(0.001 \mathrm{M} \mathrm{CaCl}_{2}\) and \(0.001 \mathrm{M} \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\)
- D \(0.01 \mathrm{M} \mathrm{BaCl}_{2}\) and \(0.001 \mathrm{M} \mathrm{CaCl}_{2}\)
Answer & Solution
Correct Answer
(A) \(0.01 \mathrm{M} \mathrm{BaCl}_{2}\) and \(0.015 \mathrm{M} \mathrm{NaCl}\)
Step-by-step Solution
Detailed explanation
To solutions are isotonic, if their osmotic pressure are same.
Here, \(0.01 \mathrm{M} \mathrm{BaCl}_{2}\) and \(0.015 \mathrm{M} \mathrm{NaCl}\) will have same value of osmotic pressure.
We know, \(\pi=C R T\)
Here, \(R\) and \(T\) are constant and their value is same for both the solutions.
\(\pi=C_{\text {effective }} R T\)
If \(C_{\text {effective }}\) of two solutions are equal then their osmotic pressures will also be equal.
So, option (a) has equal value of \(C_{\text {effective }}\) and hence, this pair will be isotonic.
Here, \(0.01 \mathrm{M} \mathrm{BaCl}_{2}\) and \(0.015 \mathrm{M} \mathrm{NaCl}\) will have same value of osmotic pressure.
We know, \(\pi=C R T\)
Here, \(R\) and \(T\) are constant and their value is same for both the solutions.
\(\pi=C_{\text {effective }} R T\)
If \(C_{\text {effective }}\) of two solutions are equal then their osmotic pressures will also be equal.
So, option (a) has equal value of \(C_{\text {effective }}\) and hence, this pair will be isotonic.
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