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KCET · Chemistry · Coordination Compounds

The oxidation state of \(\mathrm{Fe}\) in the brown ring complex: \(\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right] \mathrm{SO}_{4}\) is

  1. A \(+3\)
  2. B 0
  3. C \(+2\)
  4. D \(+1\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(+1\)

Step-by-step Solution

Detailed explanation

Let the oxidation state of \(\mathrm{Fe}\) in
\[
\begin{array}{cc}
& {\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{NO}\right]^{2+}} \\
\Rightarrow & \mathrm{x}+0+1=2 \\
\therefore & \mathrm{x}=+1
\end{array}
\]
Here \(\mathrm{NO}\) exists as nitrosyl ion \(\left(\mathrm{NO}^{+}\right)\).