KCET · Chemistry · Some Basic Concepts of Chemistry
Match List-I with List-II and select the correct option (Based on mole concept):
| List-I | List-II | ||
|---|---|---|---|
| (a) | \(2\) moles of ethene | (i) | \(11.2\) L volume at STP |
| (b) | Mass is equal to \(66\) g | (ii) | \(56\) g |
| (c) | \(1\) g of \(\text{H}_2\) | (iii) | \(12.04 \times 10^{23}\) Molecules |
| (d) | \(2\) moles of water vapours | (iv) | \(1.5\) mole of \(\text{CO}_2\) |
- A a-ii, b-iv, c-i, d-iii
- B a-iii, b-i, c-iv, d-ii
- C a-i, b-iv, c-ii, d-iii
- D a-ii, b-iii, c-i, d-iv
Answer & Solution
Correct Answer
(A) a-ii, b-iv, c-i, d-iii
Step-by-step Solution
Detailed explanation
For (a): Molar mass of ethene (\(\text{C}_2\text{H}_4\)) is \(28 \text{ g/mol}\). Mass of \(2\) moles of ethene \(= 2 \times 28 = 56 \text{ g}\). This matches with (ii).
For (b): Molar mass of \(\text{CO}_2\) is \(44 \text{ g/mol}\). Mass of \(1.5\) moles of \(\text{CO}_2 = 1.5 \times 44 = 66 \text{ g}\). This matches with (iv).
For (c): Molar mass of \(\text{H}_2\) is \(2 \text{ g/mol}\). Number of moles in \(1 \text{ g}\) of \(\text{H}_2 = \dfrac{1}{2} = 0.5 \text{ mol}\). Volume at STP \(= 0.5 \times 22.4 \text{ L} = 11.2 \text{ L}\). This matches with (i).
For (d): Number of molecules in \(2\) moles of water vapours \(= 2 \times 6.022 \times 10^{23} = 12.04 \times 10^{23}\) molecules. This matches with (iii).
The correct matching is a-ii, b-iv, c-i, d-iii.
Answer: a-ii, b-iv, c-i, d-iii
For (b): Molar mass of \(\text{CO}_2\) is \(44 \text{ g/mol}\). Mass of \(1.5\) moles of \(\text{CO}_2 = 1.5 \times 44 = 66 \text{ g}\). This matches with (iv).
For (c): Molar mass of \(\text{H}_2\) is \(2 \text{ g/mol}\). Number of moles in \(1 \text{ g}\) of \(\text{H}_2 = \dfrac{1}{2} = 0.5 \text{ mol}\). Volume at STP \(= 0.5 \times 22.4 \text{ L} = 11.2 \text{ L}\). This matches with (i).
For (d): Number of molecules in \(2\) moles of water vapours \(= 2 \times 6.022 \times 10^{23} = 12.04 \times 10^{23}\) molecules. This matches with (iii).
The correct matching is a-ii, b-iv, c-i, d-iii.
Answer: a-ii, b-iv, c-i, d-iii
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