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KCET · Chemistry · Some Basic Concepts of Chemistry

Match List-I with List-II and select the correct option (Based on mole concept):
List-IList-II
(a)\(2\) moles of ethene(i)\(11.2\) L volume at STP
(b)Mass is equal to \(66\) g(ii)\(56\) g
(c)\(1\) g of \(\text{H}_2\)(iii)\(12.04 \times 10^{23}\) Molecules
(d)\(2\) moles of water vapours(iv)\(1.5\) mole of \(\text{CO}_2\)

  1. A a-ii, b-iv, c-i, d-iii
  2. B a-iii, b-i, c-iv, d-ii
  3. C a-i, b-iv, c-ii, d-iii
  4. D a-ii, b-iii, c-i, d-iv
Verified Solution

Answer & Solution

Correct Answer

(A) a-ii, b-iv, c-i, d-iii

Step-by-step Solution

Detailed explanation

For (a): Molar mass of ethene (\(\text{C}_2\text{H}_4\)) is \(28 \text{ g/mol}\). Mass of \(2\) moles of ethene \(= 2 \times 28 = 56 \text{ g}\). This matches with (ii).

For (b): Molar mass of \(\text{CO}_2\) is \(44 \text{ g/mol}\). Mass of \(1.5\) moles of \(\text{CO}_2 = 1.5 \times 44 = 66 \text{ g}\). This matches with (iv).

For (c): Molar mass of \(\text{H}_2\) is \(2 \text{ g/mol}\). Number of moles in \(1 \text{ g}\) of \(\text{H}_2 = \dfrac{1}{2} = 0.5 \text{ mol}\). Volume at STP \(= 0.5 \times 22.4 \text{ L} = 11.2 \text{ L}\). This matches with (i).

For (d): Number of molecules in \(2\) moles of water vapours \(= 2 \times 6.022 \times 10^{23} = 12.04 \times 10^{23}\) molecules. This matches with (iii).

The correct matching is a-ii, b-iv, c-i, d-iii.

Answer: a-ii, b-iv, c-i, d-iii