KCET · Chemistry · Coordination Compounds
How many ions per molecule are produced in the solution when Mohr salt is dissolved in
excess of water?
- A \( 04 \)
- B \( 05 \)
- C \( 06 \)
- D \( 10 \)
Answer & Solution
Correct Answer
(B) \( 05 \)
Step-by-step Solution
Detailed explanation
The Mohr salt is a double salt of iron and ammoniumsulphates, therefore, on dissociation of the Mohr salt into water it
dissociates to \( \mathrm{Fe}^{2+}, \mathrm{NH}_{4}^{+} \)and \( \mathrm{SO}_{4}{ }^{2-} \) ions.
\(\mathrm{FeSO}_{4} \cdot\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}_{-} \) Excess \( \mathrm{H}_{2} \mathrm{O}\)
Therefore, total number of ions \( =(1)+(2)+(2)=5 \)
dissociates to \( \mathrm{Fe}^{2+}, \mathrm{NH}_{4}^{+} \)and \( \mathrm{SO}_{4}{ }^{2-} \) ions.
\(\mathrm{FeSO}_{4} \cdot\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}_{-} \) Excess \( \mathrm{H}_{2} \mathrm{O}\)
Therefore, total number of ions \( =(1)+(2)+(2)=5 \)
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