KCET · Chemistry · Structure of Atom
A \(6 \%\) solution of urea is isotonic with
- A \(1 \mathrm{M}\) solution of glucose
- B \(0.05 \mathrm{M}\) solution of glucose
- C \(6 \%\) solution of glucose
- D \(25 \%\) solution of glucose
Answer & Solution
Correct Answer
(A) \(1 \mathrm{M}\) solution of glucose
Step-by-step Solution
Detailed explanation
Molarity of urea \(=\frac{\frac{6}{60}}{\frac{100}{1000}}=1 \mathrm{M}\)
Hence, \(1 \mathrm{M}\) solution of glucose is isotonic with \(6 \%\) urea solution.
Hence, \(1 \mathrm{M}\) solution of glucose is isotonic with \(6 \%\) urea solution.
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- The alkyl halides required to prepare

by Wurtz reaction areKCET 2019 Medium - Alkali metals have negative reduction potential and hence they behave asKCET 2013 Easy
- Hinsberg's reagent isKCET 2020 Medium
- Which of the following is an intensive property?KCET 2007 Medium
- \(+I\) effect is shown byKCET 2007 Easy
- In chromite ore, the oxidation number of iron and chromium are respectivelyKCET 2011 Medium
More PYQs from KCET
- According to crystal field theory, the \( M \) - Lbond in a complex isKCET 2017 Easy
- A proton moves with a velocity of \(5 \times 10^6 \hat{\mathbf{j} \mathrm{ms}^{-1}}\) through the uniform electric field, \(\mathbf{E}=4 \times 10^6[2 \hat{\mathbf{i}}+0.2 \hat{\mathbf{j}}+0.1 \hat{\mathbf{k}}] \mathrm{Vm}^{-1}\) and the uniform magnetic field \(\mathbf{B}=0.2 \hat{\mathbf{i}}+0.2 \hat{\mathbf{j}}+\hat{\mathbf{k}}] \mathrm{T}\). The approximate net force acting on the proton isKCET 2022 Medium
- Area bounded by \( y=x^{3}, y=8 \) and \( x=0 \) isKCET 2015 Easy
- Which of the following is not true?KCET 2016 Easy
- A capacitor of capacitance \( C \) charged by an amount \( Q \) is connected in parallel with an
uncharged capacitor of capacitance 2C. The final charges on the capacitors areKCET 2019 Hard - The eccentric angle of the point \((2, \sqrt{3})\) lying on \(\frac{x^{2}}{16}+\frac{y^{2}}{4}=1\) isKCET 2010 Easy