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JEE Mains · Maths · STD 11 - 12. limits
The value of \(\mathop {\lim }\limits_{x \to 0} \frac{1}{x}\,\left[ {{{\tan }^{ - 1}}\,\left( {\frac{{x + 1}}{{2x + 1}}} \right) - \frac{\pi }{4}} \right]\) is
- A \(1\)
- B \( - \frac{1}{2}\)
- C \(2\)
- D \(0\)
Answer & Solution
Correct Answer
(B) \( - \frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\,\,\mathop {\lim }\limits_{x \to 0} \left( {\frac{1}{x}} \right)\left[ {{{\tan }^{ - 1}}\left( {\frac{{x + 1}}{{2x + 1}}} \right) - \frac{\pi }{4}} \right]\)…
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