JEE Mains · Maths · STD 12 - 7.2 definite integral
The value of the definite integral \(\int_{\pi / 24}^{5 \pi / 24} \frac{d x}{1+\sqrt[3]{\tan 2 x}} \text { is }\)
- A \(\frac{\pi}{18}\)
- B \(\frac{\pi}{3}\)
- C \(\frac{\pi}{6}\)
- D \(\frac{\pi}{12}\)
Answer & Solution
Correct Answer
(D) \(\frac{\pi}{12}\)
Step-by-step Solution
Detailed explanation
Let \(I=\int_{\pi / 24}^{5 \pi / 24} \frac{(\cos 2 x)^{1 / 3}}{(\cos 2 x)^{1 / 3}+(\sin 2 x)^{1 / 3}} d x.....(i)\)…
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