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JEE Mains · Maths · STD 12 - 9. differential equations

The curve satisfying the differential equation, \((x^2 -y^2) \,dx + 2xydy\, = 0\) and passing through the point \((1 , 1 )\) is

  1. A a circle of radius two
  2. B a circle of radius one
  3. C a hyprbola
  4. D an ellipse
Verified Solution

Answer & Solution

Correct Answer

(B) a circle of radius one

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=\frac{y^{2}-x^{2}}{2 x y}\) put \(y=u x\) \(\frac{d y}{d x}=u+x \frac{d u}{d x}\) \(u+x \frac{d u}{d x}=\frac{u^{2}-1}{2 u}\) \(\Rightarrow x \frac{d u}{d x}=\frac{u^{2}-1-2 u^{2}}{2 u}\) \(\Rightarrow \quad=\frac{-1-u^{2}}{2 u}\)…
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