JEE Mains · Maths · STD 12 - 8. Application and integration
The area enclosed between the curves \(y=x|x|\) and \(\mathrm{y}=\mathrm{x}-|\mathrm{x}|\) is :
- A \(\frac{8}{3}\)
- B \(\frac{2}{3}\)
- C \(1\)
- D \(\frac{4}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{4}{3}\)
Step-by-step Solution
Detailed explanation
\(A=\int_{-2}^0-x^2-2 x=\frac{4}{3}\)
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