JEE Mains · Maths · STD 12 - 8. Application and integration
The area enclosed between the curves \(y^2+4 x=4 \text { and } y-2 x=2 \text { is}\)
- A \(\frac{25}{3}\)
- B \(\frac{22}{3}\)
- C \(9\)
- D \(\frac{23}{3}\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
\begin{array}{l} y ^2+4 x =4 \\ y ^2=-4( x -1) \\ A =\int_{-4}^2\left(\frac{4- y ^2}{4}-\frac{ y -2}{2}\right) dy \\ =\left[2 y-\frac{y^3}{12}-\frac{y^2}{4}\right]_{-4}^2 \\ =\left(4-\frac{2}{3}-1\right)-\left(-8+\frac{16}{3}-4\right) \\ =3+12-\frac{18}{3} \\ =15-6 \\…
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