JEE Mains · Maths · STD 12 - 11. three dimension geometry
If \((x, y, z)\) be an arbitrary point lying on a plane \(P\) which passes through the point \((42,0,0) , (0,42,0)\) and \((0,0,42),\) then the value of expression \(3+\frac{x-11}{(y-19)^{2}(z-12)^{2}}+\frac{y-19}{(x-11)^{2}(z-12)^{2}}\)\( +\frac{z-12}{(x-11)^{2}(y-19)^{2}}-\frac{x+y+z}{14(x-11)(y-19)(z-12)} \)
- A \(0\)
- B \(3\)
- C \(39\)
- D \(-45\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
Plane passing through \((42,0,0),(0,42,0),(0,0,42)\) From intercept from, equation of plane is \(x+y+z=42\) \(\Rightarrow(x-11)+(y-19)+(z-12)=0\) let \(\quad a=x-11, b=y-19, c=z-12\) \(a+b+c=0\) Now, given expression is…
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