JEE Mains · Maths · STD 11 - 10.2 parabola,ellipse,hyperbola
If \(\alpha x+\beta y=109\) is the equation of the chord of the ellipse \(\frac{x^2}{9}+\frac{y^2}{4}=1\), whose mid point is \(\left(\frac{5}{2}, \frac{1}{2}\right)\), then \(\alpha+\beta\) is equal to :
- A 58
- B 46
- C 37
- D 72
Answer & Solution
Correct Answer
(A) 58
Step-by-step Solution
Detailed explanation
Equation of chord T \(=\mathrm{S}_1\)…
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