JEE Mains · Maths · STD 11 - 12. limits
If \(\mathop {\lim }\limits_{x - 1} \frac{{{x^4} - 1}}{{x - 1}} = \mathop {\lim }\limits_{x - k} \frac{{{x^3} - {k^3}}}{{{x^2} - {k^2}}}\), then \(k\) is
- A \(\frac{3}{8}\)
- B \(\frac{8}{3}\)
- C \(\frac{4}{3}\)
- D \(\frac{3}{2}\)
Answer & Solution
Correct Answer
(B) \(\frac{8}{3}\)
Step-by-step Solution
Detailed explanation
\(\mathop {\lim }\limits_{x \to 1} \frac{{{x^4} - 1}}{{x - 1}} = \mathop {\lim }\limits_{x \to 1} \left( {x + 1} \right)\left( {{x^2} + 1} \right)......\left( 1 \right)\)…
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