JEE Mains · Maths · STD 11 - 6. permutation and combination
If all the six digit numbers \(x_1 x_2 x_3 x_4 x_5 x_6\) with \(0 < x_1 < x_2 < x_3 < x_4 < x_5 < x_6\) are arranged in the increasing order, then the sum of the digits in the \(72^{\text {th }}\) number is \(............\).
- A \(16\)
- B \(8\)
- C \(32\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(32\)
Step-by-step Solution
Detailed explanation
\(245678 \rightarrow 72^{\text {th }} \text { word }\) \(2+4+5+6+7+8=32\)
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