JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
If \(a+x=b+y=c+z+1,\) where \(a, b, c, x, y, z\) are non-zero distinct real numbers, then \(\left|\begin{array}{lll}x & a+y & x+a \\ y & b+y & y+b \\ z & c+y & z+c\end{array}\right|\) is equal to
- A \(0\)
- B \(y(a-b)\)
- C \(y(b-a)\)
- D \(y(a-c)\)
Answer & Solution
Correct Answer
(B) \(y(a-b)\)
Step-by-step Solution
Detailed explanation
\(a+x=b+y=c+z+1\) \(\left|\begin{array}{lll}x & a+y & x+a \\ y & b+y & y+b \\ z & c+y & z+c\end{array}\right| \quad \quad C_{3} \rightarrow C_{3}-C_{1}\)…
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