JEE Mains · Maths · STD 11 - 9. straight line
If a straight line passing through the point \(P(-3, 4)\) is such that its intercepted portion between the coordinate axes is bisected at \(P,\) then its equation is
- A \(3x-4y+25=0\)
- B \(4x-3y+24=0\)
- C \(x-y+7=0\)
- D \(4x+3y=0\)
Answer & Solution
Correct Answer
(B) \(4x-3y+24=0\)
Step-by-step Solution
Detailed explanation
Let the line be \(\frac{x}{a} + \frac{y}{b} = 1\) \(\left( { - 3,4} \right) = \left( {\frac{a}{2},\frac{b}{2}} \right)\) \(a=-6, b=8\) equation of line is \(4x-3y+24=0\)
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