JEE Mains · Maths · STD 12 - 3 and 4 . metrices and determinant
If \(\mathrm{a}_{\mathrm{r}}=\cos \frac{2 \mathrm{r} \pi}{9}+i \sin \frac{2 \mathrm{r} \pi}{9}, \mathrm{r}=1,2,3, \ldots, i=\sqrt{-1}\) then the determinant \(\left|\begin{array}{lll}a_{1} & a_{2} & a_{3} \\ a_{4} & a_{5} & a_{6} \\ a_{7} & a_{8} & a_{9}\end{array}\right|\) is equal to :
- A \(a_{2} a_{6}-a_{4} a_{8}\)
- B \(\mathrm{a}_{9}\)
- C \(a_{1} a_{9}-a_{3} a_{7}\)
- D \(\mathrm{a}_{5}\)
Answer & Solution
Correct Answer
(C) \(a_{1} a_{9}-a_{3} a_{7}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{a}_{\mathrm{r}}=\mathrm{e}^{\frac{\mathrm{i} 2 \pi \mathrm{r}}{9}}, \mathrm{r}=1,2,3, \ldots \mathrm{a}_{1}, \mathrm{a}_{2}, \mathrm{a}_{3}, \ldots\) are in \(G.P.\)…
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