JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The type of hybridisation and number of lone pair\((s)\) of electrons of \(Xe\) in \(XeOF_4\) respectively are
- A \(sp^3d^2\) and \(1\)
- B \(sp^3d\) and \(2\)
- C \(sp^3d^2\) and \(2\)
- D \(sp^3d\) and \(1\)
Answer & Solution
Correct Answer
(A) \(sp^3d^2\) and \(1\)
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