JEE Mains · Chemistry · STD 11 - 9. Hydricarbon
The major product of the following reaction is \(\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,Br\,\,}
\end{array}\xrightarrow[\begin{subarray}{l}
(ii)\,NaN{H_2} \\
in\,liq.\,N{H_3}
\end{subarray} ]{{(i)\,KOH\,alc.}}\)
- A \(CH_3CH = C = CH_2\)
- B \(\begin{array}{*{20}{c}}
{C{H_3}C{H_2}CH - C{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,N{H_2}\,\,\,\,\,\,\,\,\,N{H_2}\,\,}
\end{array}\) - C \(CH_3CH=CHCH_2NH_2\)
- D \(C{H_3}C{H_2}C \equiv CH\)
Answer & Solution
Correct Answer
(D) \(C{H_3}C{H_2}C \equiv CH\)
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